Solution to Project Euler problem 70
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! Copyright (c) 2009 Aaron Schaefer.
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! See http://factorcode.org/license.txt for BSD license.
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USING: arrays byte-arrays fry hints kernel math math.combinatorics
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math.functions math.parser math.primes project-euler.common sequences sets ;
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USING: arrays byte-arrays fry kernel math math.combinatorics math.functions
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math.parser math.primes project-euler.common sequences sets ;
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IN: project-euler.049
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! http://projecteuler.net/index.php?section=problems&id=49
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@ -25,16 +25,6 @@ IN: project-euler.049
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<PRIVATE
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: count-digits ( n -- byte-array )
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10 <byte-array> [
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'[ 10 /mod _ [ 1 + ] change-nth dup 0 > ] loop drop
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] keep ;
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HINTS: count-digits fixnum ;
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: permutations? ( n m -- ? )
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[ count-digits ] bi@ = ;
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: collect-permutations ( seq -- seq )
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[ V{ } clone ] [ dup ] bi* [
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dupd '[ _ permutations? ] filter
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@ -0,0 +1,4 @@
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USING: project-euler.070 tools.test ;
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IN: project-euler.070.tests
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[ 8319823 ] [ euler070 ] unit-test
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@ -0,0 +1,67 @@
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! Copyright (c) 2010 Aaron Schaefer. All rights reserved.
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! The contents of this file are licensed under the Simplified BSD License
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! A copy of the license is available at http://factorcode.org/license.txt
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USING: arrays assocs combinators.short-circuit kernel math math.combinatorics
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math.functions math.primes math.ranges project-euler.common sequences ;
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IN: project-euler.070
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! http://projecteuler.net/index.php?section=problems&id=70
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! DESCRIPTION
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! -----------
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! Euler's Totient function, φ(n) [sometimes called the phi function], is used
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! to determine the number of positive numbers less than or equal to n which are
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! relatively prime to n. For example, as 1, 2, 4, 5, 7, and 8, are all less
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! than nine and relatively prime to nine, φ(9)=6. The number 1 is considered to
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! be relatively prime to every positive number, so φ(1)=1.
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! Interestingly, φ(87109)=79180, and it can be seen that 87109 is a permutation
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! of 79180.
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! Find the value of n, 1 < n < 10^(7), for which φ(n) is a permutation of n and
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! the ratio n/φ(n) produces a minimum.
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! SOLUTION
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! --------
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! For n/φ(n) to be minimised, φ(n) must be as close to n as possible; that is,
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! we want to maximise φ(n). The minimal solution for n/φ(n) would be if n was
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! prime giving n/(n-1) but since n-1 never is a permutation of n it cannot be
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! prime.
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! The next best thing would be if n only consisted of 2 prime factors close to
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! (in this case) sqrt(10000000). Hence n = p1*p2 and we only need to search
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! through a list of known prime pairs. In addition:
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! φ(p1*p2) = p1*p2*(1-1/p1)(1-1/p2) = (p1-1)(p2-1)
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! ...so we can compute φ(n) more efficiently.
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<PRIVATE
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! NOTE: ±1000 is an arbitrary range
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: likely-prime-factors ( -- seq )
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7 10^ sqrt >integer 1000 [ - ] [ + ] 2bi primes-between ; inline
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: n-and-phi ( seq -- seq' )
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#! ( seq = { p1, p2 } -- seq' = { n, φ(n) } )
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[ product ] [ [ 1 - ] map product ] bi 2array ;
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: fit-requirements? ( seq -- ? )
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first2 { [ drop 7 10^ < ] [ permutations? ] } 2&& ;
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: minimum-ratio ( seq -- n )
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[ [ first2 / ] map [ infimum ] keep index ] keep nth first ;
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PRIVATE>
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: euler070 ( -- answer )
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likely-prime-factors 2 all-combinations [ n-and-phi ] map
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[ fit-requirements? ] filter minimum-ratio ;
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! [ euler070 ] 100 ave-time
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! 379 ms ave run time - 1.15 SD (100 trials)
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SOLUTION: euler070
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! Copyright (c) 2007-2010 Aaron Schaefer.
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! See http://factorcode.org/license.txt for BSD license.
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USING: accessors arrays kernel lists make math math.functions math.matrices
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math.primes.miller-rabin math.order math.parser math.primes.factors
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math.primes.lists math.ranges math.ratios namespaces parser prettyprint
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quotations sequences sorting strings unicode.case vocabs vocabs.parser
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words ;
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! The contents of this file are licensed under the Simplified BSD License
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! A copy of the license is available at http://factorcode.org/license.txt
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USING: accessors arrays byte-arrays fry hints kernel lists make math
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math.functions math.matrices math.order math.parser math.primes.factors
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math.primes.lists math.primes.miller-rabin math.ranges math.ratios
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namespaces parser prettyprint quotations sequences sorting strings
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unicode.case vocabs vocabs.parser words ;
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IN: project-euler.common
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! A collection of words used by more than one Project Euler solution
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@ -25,6 +26,7 @@ IN: project-euler.common
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! pentagonal? - #44, #45
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! penultimate - #69, #71
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! propagate-all - #18, #67
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! permutations? - #49, #70
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! sum-proper-divisors - #21
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! tau* - #12
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! [uad]-transform - #39, #75
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<PRIVATE
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: count-digits ( n -- byte-array )
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10 <byte-array> [
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'[ 10 /mod _ [ 1 + ] change-nth dup 0 > ] loop drop
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] keep ;
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HINTS: count-digits fixnum ;
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: max-children ( seq -- seq )
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[ dup length 1 - iota [ nth-pair max , ] with each ] { } make ;
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reverse [ first dup ] [ rest ] bi
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[ propagate dup ] map nip reverse swap suffix ;
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: permutations? ( n m -- ? )
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[ count-digits ] bi@ = ;
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: sum-divisors ( n -- sum )
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dup 4 < [ { 0 1 3 4 } nth ] [ (sum-divisors) ] if ;
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