97 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			Factor
		
	
	
			
		
		
	
	
			97 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			Factor
		
	
	
! Copyright (c) 2008 Aaron Schaefer.
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! See http://factorcode.org/license.txt for BSD license.
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USING: arrays kernel math math.primes math.primes.factors
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    math.ranges namespaces sequences project-euler.common ;
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IN: project-euler.047
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! http://projecteuler.net/index.php?section=problems&id=47
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! DESCRIPTION
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! -----------
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! The first two consecutive numbers to have two distinct prime factors are:
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!     14 = 2 * 7
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!     15 = 3 * 5
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! The first three consecutive numbers to have three distinct prime factors are:
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!     644 = 2² * 7 * 23
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!     645 = 3 * 5 * 43
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!     646 = 2 * 17 * 19.
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! Find the first four consecutive integers to have four distinct primes
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! factors. What is the first of these numbers?
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! SOLUTION
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! --------
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! Brute force, not sure why it's incredibly slow compared to other languages
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<PRIVATE
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: (consecutive) ( count goal test -- n )
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    2over = [
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        swap - nip
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    ] [
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        dup prime? [ [ drop 0 ] 2dip ] [
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            2dup unique-factors length = [ [ 1 + ] 2dip ] [ [ drop 0 ] 2dip ] if
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        ] if 1 + (consecutive)
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    ] if ;
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: consecutive ( goal test -- n )
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    0 -rot (consecutive) ;
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PRIVATE>
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: euler047 ( -- answer )
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    4 646 consecutive ;
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! [ euler047 ] time
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! 344688 ms run / 20727 ms GC time
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! ALTERNATE SOLUTIONS
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! -------------------
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! Use a sieve to generate prime factor counts up to an arbitrary limit, then
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! look for a repetition of the specified number of factors.
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<PRIVATE
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SYMBOL: sieve
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: initialize-sieve ( n -- )
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    0 <repetition> >array sieve set ;
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: is-prime? ( index -- ? )
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    sieve get nth 0 = ;
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: multiples ( n -- seq )
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    sieve get length 1 - over <range> ;
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: increment-counts ( n -- )
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     multiples [ sieve get [ 1 + ] change-nth ] each ;
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: prime-tau-upto ( limit -- seq )
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    dup initialize-sieve 2 swap [a,b) [
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        dup is-prime? [ increment-counts ] [ drop ] if
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    ] each sieve get ;
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: consecutive-under ( m limit -- n/f )
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    prime-tau-upto [ dup <repetition> ] dip subseq-start ;
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PRIVATE>
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: euler047a ( -- answer )
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    4 200000 consecutive-under ;
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! [ euler047a ] 100 ave-time
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! 331 ms ave run time - 19.14 SD (100 trials)
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! TODO: I don't like that you have to specify the upper bound, maybe try making
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! this lazy so it could also short-circuit when it finds the answer?
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SOLUTION: euler047a
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